Answer:
4,000 Kilojoules (2 sig. figs. based on 2 sig. figs. in 75Kg water).
Explanation:
Energy change equation => q = m·c·ΔT
q = total amount of heat flow
m = mass in grams = 75,000 grams
c = specific heat of water = 4.184 joules/gram·°C
ΔT = Temperature change in °C = 22.4°C - 9.8°C = 12.6°C
q =(75,000g)(4.184j/g·°C)(12.6°C) = 3,953,880 joules = 3,954 Kilojoules ≅ 4,000 Kilojoules (2 sig. figs. based on 2 sig. figs. in 75Kg water).
