20. Using a Z-score table. Fernando is 60 inches tall. The
average height for his age and gender is 68 with a standard
deviation of 10 inches. What percent of his peers are
shorter than him?
a) 46.81%
b) 8%
c) 78.81%
d) 21.19%

Respuesta :

Answer:

The correct option is (d) 21.19%.

Step-by-step explanation:

Let the random variable X denote the heights of Fernando's peers.

The mean and standard deviation of the random variable X are:

μ = 68 inches

σ = 10 inches

It is provided that Fernando is 60 inches tall.

Compute the value of P (X < 60) as follows:

[tex]P(X<60)=P(\frac{X-\mu}{\sigma}<\frac{60-68}{10})[/tex]

                  [tex]=P(Z<-0.80)\\=1-P(Z<0.80)\\=1-0.78814\\=0.21186\\\approx 0.2119[/tex]

*Use a z-table.

The percentage is, 0.2119 × 100 = 21.19%.

Thus, the percentage of his peers are  shorter than Fernando is 21.19%.

The correct option is (d).

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