Respuesta :
Answer : The molarity of a solution is, 4.88 M
Explanation : Given,
Mass of [tex]AlCl_3[/tex] = 325.4 g
Volume of solution = 500.0 mL
Molar mass of [tex]AlCl_3[/tex] = 133.34 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }AlCl_3\times 1000}{\text{Molar mass of }AlCl_3\times \text{Volume of solution (in mL)}}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{Molarity}=\frac{325.4g\times 1000}{133.34g/mole\times 500.0mL}=4.88mole/L=4.88M[/tex]
Therefore, the molarity of a solution is, 4.88 M
Answer: The molarity of solution is 4.880 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
mass of [tex]AlCl_3[/tex] = [tex]\frac{\text {given mass}}{\text {Molar Mass}}=\frac{325.4g}{133.34g/mol}=2.440[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molality=\frac{2.440\times 1000}{500ml}=4.880mole/L[/tex]
Therefore, the molarity of solution is 4.880 M
