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Tim is grilling burgers for dinner. He uses 15.0g of propane. Given that the combustion of propane releases 2,220 kJ/mol and that the molecular weight of propane is 44.097 g/mol, calculate the enthalpy of the propane used for dinner.
A) 755 kJ
B) 1,390 kJ
C) 2,130 kJ
D) 6,530 kJ

Respuesta :

drpelezo

Answer:

Heat Enthalpy used = 755 Kilojoules

Explanation:

15 grams propane = (15g/44.097g·mol⁻¹) = 0.3402mol propane

Heat Enthalpy used = 0.3402mol X 2,220Kj/mol = 755 Kilojoules

miillerdani9
A.

Hopefully it works

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