Answer:
Step-by-step explanation:
Area of polygon = Area of triangle + Area of trapezium
Triangle: ΔEFD
base b = 15 m
height h = 7 m
[tex]Area=\frac{1}{2}bh\\\\=\frac{1}{2}*15*7\\\\=\frac{105}{2}\\\\=52.5cm^{2}\\[/tex]
Trapizium ABCF:
Parallel sides a = 15+ 9 = 24m and b = 15 m
h = 8 m
[tex]Area=\frac{(a+b)h}{2}\\=\frac{(24+15)*8}{2}\\\\=\frac{39*8}{2}\\\\=39*4[/tex]
= 156 m²
Area of polygon = Area of triangle + Area of trapezium
= 52.5 + 156
= 208.5 m²
