Answer:
Step-by-step explanation:
Volume of first container = 48 cm³
πr²h = 48 cm³
Second container:
height = (2/3)h
Volume of second container=
[tex]=\pi *r^{2}*(\frac{2}{3}*h)\\\\=\frac{2}{3}*\pi *r^{2}*h\\\\[/tex]
=(2/3)* first container's volume {πr²h = 48 cm³}
[tex]=\frac{2}{3}*48\\\\=2*16\\\\[/tex]
= 32 cm³
