A removable discontinuity happens where y=(0/0).
First factor the numerator and denominator.
Factor the GCF from the numerator, which would be 5:
Factoring 5 out of 5x gives us x, and factoring 5 out of 10 gives us 2, which now gives us 5(x+2)
Now to factor the denominator, we want factors of c, 10, that sum to b, 7: 5*2=10 and 5+2=7, so this will give us (x+5)(x+2).
Now we have:
5(x+2) / (x+5)(x+2)
Find the common factors in both the numerator and denominator:
(x+2) is the common factor. Set this equal to zero and solve for x:
x+2=0 x = -2
The answer would be x = -2
