Respuesta :
4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
4x + 4 - ax = x + 5
- x - x
3x + 4 - ax = 5
- 4 - 4
3x - ax = 1
x(3) - x(a) = 1
x(3 - a) = 1
3 - a 3 - a
x = 1/(3 - a)
4(x) + 4(1) - ax = x + 5
4x + 4 - ax = x + 5
- x - x
3x + 4 - ax = 5
- 4 - 4
3x - ax = 1
x(3) - x(a) = 1
x(3 - a) = 1
3 - a 3 - a
x = 1/(3 - a)
[tex]4(x+1)-ax=x+5[/tex]
[tex]4x+4-ax=x+5 [/tex] [tex]Expand [/tex]
[tex]4x-ax=x+5-4 [/tex] [tex]Subtract \ 4 \ from \ both \ sides[/tex]
[tex]4x-ax=x+1[/tex]
[tex]4x=x+1+ax[/tex] [tex]Add \ ax \ to \ both \ sides[/tex]
[tex]4x-x=1+ax [/tex] [tex]Subtract \ x \ from \ both \ sides[/tex]
[tex]3x=1+ax [/tex]
[tex]3x-ax=1 [/tex] [tex]Subtract \ ax \ from \ both \ sides[/tex]
[tex]x(3-a)=1 [/tex]
[tex]x= \dfrac{1}{3-a} [/tex]
[tex]4x+4-ax=x+5 [/tex] [tex]Expand [/tex]
[tex]4x-ax=x+5-4 [/tex] [tex]Subtract \ 4 \ from \ both \ sides[/tex]
[tex]4x-ax=x+1[/tex]
[tex]4x=x+1+ax[/tex] [tex]Add \ ax \ to \ both \ sides[/tex]
[tex]4x-x=1+ax [/tex] [tex]Subtract \ x \ from \ both \ sides[/tex]
[tex]3x=1+ax [/tex]
[tex]3x-ax=1 [/tex] [tex]Subtract \ ax \ from \ both \ sides[/tex]
[tex]x(3-a)=1 [/tex]
[tex]x= \dfrac{1}{3-a} [/tex]