28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. the water level rises to the 49.10 mL mark. From this information, calculate the density of iron.

Respuesta :

Density=mass/volume.
1) we have to calculate the iron volume in liters.
iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml
3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters 

2) we calculate the mass iron in kg.
28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.
2) we calculate the density of iron.
density=0.0285 kg / 0.0036 liters=7.92 kg/L

7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.

answer: From this information the Iron density is 7.92 Kg/L or  7.92 g/cm³.

7.92 g/cm³ is the density of the iron sheet.

Density is calculated by the formula:

= Mass / Volume

The mass here is 28.5 g

The Volume is:

= Volume of water after iron shot added - Volume before shot added

= 49.10 - 45.50

= 3.6 mL

The units for density is g / cm³ so you need to convert the mL to cm³.

1 cm³ = 1 mL

3.6 mL is therefore 3.6 cm³.

Density is:

= 28.5 / 3.6

= 7.92 g / cm³

In conclusion, the density of the iron shot is 7.92 g /cm³.

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