Respuesta :
Hello,
And where are parenthesis ?
If it is a proportion we must have 4 terms
So the equation is
[tex] \dfrac{32}{4} = \dfrac{b+4}{3} \\ ==\textgreater \ \dfrac{8}{1} = \dfrac{b+4}{3} \\ ==\textgreater \ b+4 = 3*8 \\ ==\textgreater \ b = 24-4 \\ ==\textgreater \ b= 20\\[/tex]
And where are parenthesis ?
If it is a proportion we must have 4 terms
So the equation is
[tex] \dfrac{32}{4} = \dfrac{b+4}{3} \\ ==\textgreater \ \dfrac{8}{1} = \dfrac{b+4}{3} \\ ==\textgreater \ b+4 = 3*8 \\ ==\textgreater \ b = 24-4 \\ ==\textgreater \ b= 20\\[/tex]
If you would like to solve the equation 32/4 = b + 4/3, you can do this using the following steps:
32/4 = b + 4/3
8 = b + 4/3
b = 8 - 4/3
b = 24/3 - 4/3
b = 20/3
The correct result would be b = 20/3.
Otherwise:
32/4 = (b+4)/3
8 = (b + 4)/3 /*3
8 * 3 = b + 4
24 = b + 4
b = 24 - 4
b = 20
The correct result would be b = 20.
32/4 = b + 4/3
8 = b + 4/3
b = 8 - 4/3
b = 24/3 - 4/3
b = 20/3
The correct result would be b = 20/3.
Otherwise:
32/4 = (b+4)/3
8 = (b + 4)/3 /*3
8 * 3 = b + 4
24 = b + 4
b = 24 - 4
b = 20
The correct result would be b = 20.