Respuesta :
Answer: [tex]10x^2-y^2+3xy+6x+3y[/tex]
Step-by-step explanation:
Given expressions are 2x+ y and 5x -y +3
Product of 2x+y and 5x-y+3 is
[tex](2x+y)\times (5x-y+3) = 2x\times (5x-y+3) + y\times (5x-y+3)[/tex] ( by applying distributive property under multiplication over addition)
⇒[tex](2x+y)\times (5x-y+3) = 10x^2-2xy+6x+5xy-y^2+3y[/tex] (again by distributive property)
⇒[tex](2x+y)\times (5x-y+3) = 10x^2-y^2+3xy+6x+3y[/tex] ( by operating the like terms.)
Answer: The required product is [tex]10x^2-y^2+3xy+6x+3y.[/tex]
Step-by-step explanation: We are to find the product f the following two algebraic expressions:
[tex]E_1=2x+y,\\\\E_2=5x-y+3.[/tex]
To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.
The multiplication is as follows:
[tex]M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.[/tex]
Thus, the required product is [tex]10x^2-y^2+3xy+6x+3y.[/tex]
