Respuesta :
Answer:
Balanced reaction: [tex]4Zn+10HNO_{3}\rightarrow 4Zn(NO_{3})_{2}+N_{2}O+5H_{2}O[/tex]
The mole ratio (4 moles Zn/5 moles [tex]H_{2}O[/tex]) is correct.
Explanation:
Oxidation: [tex]Zn\rightarrow Zn(NO_{3})_{2}[/tex]
Balance N and O: [tex]Zn+2NO_{3}^{-}\rightarrow Zn(NO_{3})_{2}[/tex]
Balance charge: [tex]Zn+2NO_{3}^{-}-2e^{-}\rightarrow Zn(NO_{3})_{2}[/tex] ................(1)
Reduction: [tex]HNO_{3}\rightarrow N_{2}O[/tex]
Balance N: [tex]2HNO_{3}\rightarrow N_{2}O[/tex]
Balance H and O: [tex]2HNO_{3}+8H^{+}\rightarrow N_{2}O+5H_{2}O[/tex]
Balance charge: [tex]2HNO_{3}+8H^{+}+8e^{-}\rightarrow N_{2}O+5H_{2}O[/tex] ............. (2)
[[tex]4\times[/tex]Equation-(1)] + [Equation-(2)]:
[tex]4Zn+8NO_{3}^{-}+2HNO_{3}+8H^{+}\rightarrow 4Zn(NO_{3})_{2}+N_{2}O+5H_{2}O[/tex]
[tex]\Rightarrow 4Zn+10HNO_{3}\rightarrow 4Zn(NO_{3})_{2}+N_{2}O+5H_{2}O[/tex]
So, balanced reaction: [tex]4Zn+10HNO_{3}\rightarrow 4Zn(NO_{3})_{2}+N_{2}O+5H_{2}O[/tex]
Hence the mole ratio (4 moles Zn/5 moles [tex]H_{2}O[/tex]) is correct.
