Omar will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $59 and costs an additional 50.11 per mile driven. The

second plan has an initial fee of $52 and costs an additional $0.15 per mile driven

For what amount of driving do the two plans cost the

What is the cost when the two plans cost the same?

Respuesta :

Answer:

[tex] 59 +0.11 x = 52 +0.15 x[/tex]

And solving for x we got:

[tex] 7= 0.04 x[/tex]

And replacing for x we got:

[tex] x = \frac{7}{0.04}= 175[/tex]

And for the cost would be:

[tex] c_1 = 59 +0.11*175 = 78.25[/tex]

[tex] c_2 = 52 +0.15*175 = 78.25[/tex]

Step-by-step explanation:

Assuming the following info corrected :Omar will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $59 and costs an additional 0.11 per mile driven. The  second plan has an initial fee of $52 and costs an additional $0.15 per mile driven

For this case we know that the first plan has an initial fee of $59 and costs an additional 50.11 per mile driven and the second plan has an initial fee of $52 and costs an additional $0.15 per mile driven.

So we can set up the following equations for each cost

[tex] c_1 = 59 +0.11 x[/tex]

With c1 the cost of the plan 1 and x the number of miles

[tex] c_2 = 52 +0.15 x[/tex]

With c2 the cost of the plan 2 and x the number of miles

We can set equatl the two costs:

[tex] c_1 = c_2[/tex]

And replacing we got:

[tex] 59 +0.11 x = 52 +0.15 x[/tex]

And solving for x we got:

[tex] 7= 0.04 x[/tex]

And replacing for x we got:

[tex] x = \frac{7}{0.04}= 175[/tex]

And for the cost would be:

[tex] c_1 = 59 +0.11*175 = 78.25[/tex]

[tex] c_2 = 52 +0.15*175 = 78.25[/tex]