Respuesta :
Answer:
c) r= 2sin θ
Step-by-step explanation:
Remember, [tex]r=\sqrt{x^2+y^2} \\[/tex]
therefore,[tex]r^2=x^2+y^2[/tex]
Also y= rsin θ
Given rectangular equation:
x²+y²+ 2y
r²= 2(rsin θ)
r²= 2rsin θ
dividing r from both sides
r= 2sin θ
Answer:
c) r= 2sin θ
Step-by-step explanation:
Remember, [tex]r=\sqrt{x^2+y^2} \\[/tex]
therefore,[tex]r^2=x^2+y^2[/tex]
Also y= rsin θ
Given rectangular equation:
x²+y²+ 2y
r²= 2(rsin θ)
r²= 2rsin θ
dividing r from both sides
r= 2sin θ