Answer:
[tex]Zn^0\rightarrow Zn^{+2}+2e^-[/tex]
Explanation:
Hello,
In this case, the described chemical reaction is:
[tex]Zn(s)+HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
Then, to identify the half reactions we must assign the oxidation state for each element as shown below:
[tex]Zn^0(s)+H^+Cl^-(aq)\rightarrow Zn^{+2}Cl_2^-(aq)+H_2^0(g)[/tex]
In such a way, we can notice zinc's oxidation state changes from 0 to +2, therefore, it is the oxidizes species for which the half reaction which correctly describes the oxidation that is taking place is:
[tex]Zn^0\rightarrow Zn^{+2}+2e^-[/tex]
Best regards.
