Let f(x) be x^2+8x-6
x-2=0
x=2
f(2)=(2)^2+8(2)-6
= 4+16-6
= 20-6
= 14
(x-2) is not a factor of f(x).
x+2=0
x=-2
f(-2)=(-2)^2+8(-2)-6
= 4-16-6
= -18
(x+2) is not a factor of f(x).
x-4=0
x=4
f(4)= (4)^2+8(4)-6
= 16+32-6
= 10+32
= 42
(x-4) is not a factor of f(x).
Since none of the given factors are the factors of f(x), and the question states that one of the statements given above are true, the true statement is that the polynomial is prime.
