Answer:
[tex](6x^3 - 17x^2 + 8x - 1) (3x - 1) : 18x^4 - 57x^3 + 41x^2 - 11x + 1[/tex]
Step-by-step explanation:
[tex]( 6x^3 - 17x^2 + 8x -1 ) ( 3x - 1 )[/tex]
Distribute parentheses:
[tex]=6x^3\cdot \:3x+6x^3\left(-1\right)+\left(-17x^2\right)\cdot \:3x+\left(-17x^2\right)\left(-1\right)+8x\cdot \:3x+8x\left(-1\right)+\left(-1\right)\cdot \:3x+(-1)(-1)[/tex]
Apply minus - plus rules: [tex]+\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab[/tex]
[tex]=6\cdot \:3x^3x-6\cdot \:1\cdot \:x^3-17\cdot \:3x^2x+17\cdot \:1\cdot \:x^2+8\cdot \:3xx-8\cdot \:1\cdot \:x-1\cdot \:3x+1\cdot \:1[/tex]
Simplify:
[tex]6 * 3x^3x - 6 * 1 * x^3 - 17 * 3x^2x + 17 * 1 * x^2 + 8 * 3xx - 8 * 1 * x - 1 * 3x + 1 * 1: 18x^4 - 57x^3 + 41x^2 - 11x + 1[/tex]
Final Answer:
[tex]= 18x^4 - 57x^3 + 41x^2 - 11x + 1[/tex]
Hope I helped, if so may I get brainliest and a thanks?
Thank you, have a good day! =)
