Respuesta :

Answer:

1)(-3,4)

2)2

3)(x-0)^2+(y+5)^2=14

Step-by-step explanation:

1) so the center of a circle equation is (x-h)^2+(y-k)^2=r^2

where (h,k) are center of the circle

so as h we have 3.....but since its -h we must take -3 as x coordinate for center

and we need to take 4 as y coordinate since its -k and k=4 so-(-4)=4

center of circle: (-3,4)

since r^2represents the radius in a circle, the r^2 value is 4

to find just r we must take the square root

sqrt of 4=2

hence radius is 2

(x-0)^2+(y--5)^2=14

Answer:

1)(-3,4)

2)2

3)(x-0)^2+(y+5)^2=14

Step-by-step explanation:

1) so the center of a circle equation is (x-h)^2+(y-k)^2=r^2

where (h,k) are center of the circle

so as h we have 3.....but since its -h we must take -3 as x coordinate for center

and we need to take 4 as y coordinate since its -k and k=4 so-(-4)=4

center of circle: (-3,4)

since r^2represents the radius in a circle, the r^2 value is 4

to find just r we must take the square root

sqrt of 4=2

hence radius is 2

(x-0)^2+(y--5)^2=14

Step-by-step explanation: