A radioactive nuclide that is used for radiation therapy for cancer has 33 neutrons and a mass number of 60. Which is the correct symbol for this nuclide? Superscript 27 subscript 60 upper C o. Superscript 33 subscript 60 upper C o. Superscript 60 subscript 33 upper C o. Superscript 60 subscript 27 upper C o.

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The correct answer on Edge is D. 60/27 Co.  Superscript 60 subscript 27 Co.

The correct symbol of the nuclide given the data is superscript 60 subscript 27 upper Co (⁶⁰₂₇Co)

How to determine the number of protons

Atomic number is simply defined as the number of protons in the nucleus of the atom.

However, the proton, neutron and mass number are related according to the following equation:

Mass number = proton + neutron

From the question given above, we obtained the following:

  • Neutron = 33
  • Mass number = 60
  • Proton =?

Mass number = proton + neutron

60 = proton + 33

Collect like terms

Proton = 60 – 33

Proton = 27

How to determine the element

The nuclide has an atomic number of 27. Considering the periodic table, only cobalt has atomic number of 27.

How to determine the symbol of the nuclide

  • Mass number = 60
  • Atomic number = 27
  • Symbol of nuclide =?

The symbol of the nuclide is given as ⁶⁰₂₇Co

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