Respuesta :
Answer:
The radius of the base of the small cone is 3 feet
Step-by-step explanation:
The question requires the determination of the radius of the smaller cone
Therefore, height of the larger cone = 10 feet
Base diameter of the larger cone = 10 feet
Height of horizontal plane of small plane above base of larger cone = 4 feet
Hence the height of the small cone = 6 feet
Therefore, by similar triangles, and tangents we have;
[tex]\frac{Height \, of \, small \, cone}{Height \, of \, larger\, cone} =\frac{Diameter \, of \, base \, of \, small \, cone}{Diameter \, of \, base \, of \, larger \ cone} =\frac{6}{10} = \frac{x}{10}[/tex]
Where:
x = The diameter of the base of the small cone
Therefore;
[tex]{x} = \frac{6}{10} \times 10 = 6 \, feet[/tex]
The radius of the base of the small cone = half the diameter of the base of the small cone
∴ The radius of the base of the small cone = (6 feet)/2 = 3 feet.
Answer:
the radius would be 3
Step-by-step explanation:
so what it's saying si there;s a cone with diameter 10 and height 10, the 4 feet above the bottom of the cone is the base of the smaller cone. The height of the smaller cone becomes 6, making the diameter 6 as the ratio becomes 6:6, and radius is diameter/2 becoming 3
