Answer:
The final temperature is 414.34 degrees Celsius.
Explanation:
Gay-Lussac's law gives the relation between pressure and temperature. It states that at constant volume, pressure is directly proportional to the temperature of the gas.
[tex]P\propto T[/tex]
We have,
Initial pressure, [tex]P_1=861.05\ kPa[/tex]
Initial temperature, [tex]T_1=25^{\circ} C= 298.15\ K[/tex]
Final pressure, [tex]P_2=1985.48\ kPa[/tex]
It is required to find new temperature, using Gay-Lussac's law as:
[tex]\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}[/tex]
[tex]T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{1985.48\times 298.15}{861.05}\\\\T_2=687.49\ K[/tex]
or
[tex]T_2=414.34^{\circ} C[/tex]
So, the final temperature is 414.34 degrees Celsius.
