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7. Isosceles triangle ABC is shown below with legs that measure 8 inches and a vertex angle of 50D. (a) Determine the area of ABC ' . Note that you will need to use right triangle trigonometry. Round to the nearest tenth of a square inch.

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Answer:

The area of the triangle ABC is 32 square inches.

Step-by-step explanation:

We know that the given triangle is a right-isosceles triangle, which means its leg are equal.

The area of a triangle is defined as

[tex]A=\frac{1}{2}bh[/tex]

Where [tex]b=8[/tex] and [tex]h=8[/tex]. Replacing values, we have

[tex]A=\frac{1}{2} \times 8 \times 8 = 32 \ in^{2}[/tex]

Therefore, the area of the triangle ABC is 32 square inches.

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The area of ABC is 32 square inches.

What is Area of Triangle?

The area of Triangle is the half of the product of the base and height.

i.e., Area of Triangle= 1/2*base*height.

As, the base= 8 inches and height= 8 inches.

Area of Triangle= 1/2*base*height

                          =1/2*8*8

                          =32 square inches.

Hence, the area of triangle is 32 square inches.

Learn more about area of triangle here:

https://brainly.com/question/461184

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