Answer:
No real solutions
Step-by-step explanation:
Solution 1
From the first look, the equation has to have two positive roots as all coefficients (a,b,c) are positive
Since the are no two positive solutions given as an option, the last choice is correct
Solution 2
- 3x^2 + 2x + 7 = 0
- x^2 + 2x + 1 + 2x^2 + 6 = 0
- (x + 1)^2 + 2x^2 + 6 = 0
As we see all terms are positive, therefore there are no real solutions
Solution 3
- D = b^2 - 4ac = 2^2 - 4*3*7 = 4 - 84 = -80
Since discriminant is negative, there are no real solutions
