Find the surface area of the regular pyramid. Write your answer as a decimal.

Answer:
322.5 in²
Step-by-step explanation:
1 base triangle + 3 top triangles
(½×15×13) + 3(½×10×15)
322.5
The surface area of the regular pyramid 322.5 [tex]inch^{2}[/tex]
The surface area of a pyramid is a measure of the total area that is occupied by all its faces.
Surface Area= [tex]\frac{1}{2} * base\; area + \frac{3}{2} * base\; length* height[/tex]
The Surface area of Triangular based pyramid is:
Surface Area= [tex]\frac{1}{2} * base\; area + \frac{3}{2} * base\; length* height[/tex]
= 0.5 x 15 x 13 + 1.5 x 15 x 10
= 97.5 + 225
= 322.5 [tex]inch^{2}[/tex]
Hence, the surface area of the regular prism be : 322.5 [tex]inch^{2}[/tex]
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