Answer:
[tex]\frac{\sqrt{2} }{2}\,\,foot[/tex]
Step-by-step explanation:
Given: Four corners of a square chessboard touch the edge of a round table. The length of the chessboard is 1 foot.
To find: length of the radius of the table
Solution:
Diameter of the round table is equal to the diagonal of a square chessboard.
Diagonal of a square chessboard = [tex]\sqrt{2}[/tex] × side of the square chessboard
Here, side of a square chessboard = 1 foot
So,
Diagonal of a square chessboard = [tex]\sqrt{2}[/tex] × 1 = [tex]\sqrt{2}[/tex] foot
Diameter of the round table = Diagonal of a square chessboard = [tex]\sqrt{2}[/tex] foot
Radius of the round table = Diameter of the round table/2
= [tex]\frac{\sqrt{2} }{2}\,\,foot[/tex]
