Answer:
a) The modal class for this case represent the class with the highest frequency
And for this case would be [tex] 24 <a<26[/tex] with the highest frequency 8
b) [tex] \bar X = \frac{19*3 + 21*2 + 23*7 +25*8}{3+2+7+8} =23[/tex]
Step-by-step explanation:
Part a
The modal class for this case represent the class with the highest frequency
And for this case would be [tex] 24 <a<26[/tex] with the highest frequency 8
Part b
For this case we need to find the mid point of each interval:
Interval Midpoint Frequency
18-20 19 3
20-22 21 2
22-24 23 7
24-26 25 8
And we can find the sample mean with this formula:
[tex] \bar X = \frac{\sum_{i=1}^n f_i x_i}{n}[/tex]
And replacing we got:
[tex] \bar X = \frac{19*3 + 21*2 + 23*7 +25*8}{3+2+7+8} =23[/tex]
The class with the highest frequency represents the modal class for this case and for this case would be (24 < a < 26) with the highest frequency of 8 and an estimate of the mean age of these employees is 23.
Given :
The table shows the age, in years, of employees in a company.
A) The class with the highest frequency represents the modal class for this case and for this case would be (24 < a < 26) with the highest frequency 8.
B) To estimate the mean age of these employees, first, determine the midpoint.
Age Frequency Midpoint
18-20 3 19
20-22 2 21
22-24 7 23
24-26 8 25
The formula of the sample mean is given by:
[tex]\rm \bar{X} =\dfrac{\sum^{n}_{i=1}f_ix_i}{n}[/tex]
[tex]\rm \bar{X} = \dfrac{19\times 3+21\times 2 +23\times 7+25\times 8}{3+2+7+8}[/tex]
[tex]\rm \bar{X} = 23[/tex]
For more information, refer to the link given below:
https://brainly.com/question/20747890
