Answer:
1,348 Light Years
Step-by-step explanation:
In the triangle ABC attached, Lucy's distance to KA-7 is AB while her distance to KA-11 is AC.
We are to determine the distance BC from KA-7 (at point B) to KA-11 (at point C).
Using Law of Cosines
[tex]a^2=b^2+c^2-2bcCos A\\a^2=1700^2+1200^2-2(1700)(1200)Cos 52^\circ\\a^2=4330000-2511898.8193\\a^2=1818101.1807\\a=\sqrt{1818101.1807} \\a=1348.37\\a \approx 1348$ L.Y.[/tex]
Therefore, KA-7 and KA-11 are approximately 1,348 Light Years apart.
