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Aluminum will react with sulfuric acid in the following reaction.

2Al(s) + 3H2SO4(l) → Al2(SO4)3(aq) + 3H2(g)

a. How many moles of H2SO4 will react with 18 mol Al? ans: 27 mol H2SO4

b. How many moles of each product will be produced?

ans: 27 mol H2, 9 mol Al2(SO4)3

The moles of sulfuric acid reacted with the reaction has been 27 moles. The moles of hydrogen produce is 27 mol, and aluminum sulfate is 9 mol.

What is stoichiometric law?

The moles of reactant reacted in the reaction, and the moles of product produced, can be given by the stoichiometric law.

According to the stoichiometric law, the moles of product produces, and the reactant reacted is given by the stoichiometric coefficient.

In the given reaction, 3 moles of sulfuric acid reacts with 2 moles of Al. The moles of sulfuric acid reacted with 18 moles of aluminum will be given as:

[tex]\rm 2\; mol\;Al=3\;mol\;H_2SO_4\\\\18\;mol\;Al=\dfrac{3}{2}\;\times\;18\;mol\;H_2SO_4\\\\ 18\;mol\;Al\;=27\;mol\;H_2SO_4[/tex]

Thus, the moles of sulfuric acid reacted in the reaction are 27 moles.

The stoichiometric law gives the formation of 1 moles of aluminum sulfate from 2 moles of Al. The moles of aluminum sulfate produced from 18 moles Al is given as:

[tex]\rm 2\;mol\;Al=1\;mol\;Al_2(SO_4)_3\\\\18\;mol\;Al=\dfrac{1}{2}\;\times\;18\;mol\;Al_2(SO_4)_3\\\\ 18\;mol\;Al=9\;mol\;Al_2(SO_4)_3[/tex]

The moles of aluminum sulfate produced in the reaction are 9 moles.

The moles of hydrogen produced from 2 moles of Al are 3 moles. the moles of hydrogen produced from 18 mol Al has been:

[tex]\rm 2\; mol\;Al=3\;mol\;H_2\\\\18\;mol\;Al=\dfrac{3}{2}\;\times\;18\;mol\;H_2\\\\ 18\;mol\;Al\;=27\;mol\;H_2[/tex]

The moles of hydrogen produced in the reaction are 27 moles.

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