The volume of the paperweight will be 79.17 cubic inch
Prism
A solid geometric figure whose two end faces are similar, equal, and parallel rectilinear figures, and whose sides are parallelograms is known as prism
What are steps to solve this problem?
The steps are as follow:
- Let volume of pyramid be [tex]V_{1}[/tex]
- Let volume of prism be [tex]V_{2}[/tex]
- Since the floor area is triangle
∴ Area of floor = Area of triangle = ah/2
Where a=5 and h=5 from figure given
∴ Area of floor = (5*5)/2 = 12.5 sq.inch
- Now, let us find the volume of pyramid and prism as follow:
[tex]V_{1} = \frac{1}{3}sh \\V_{1} = \frac{1}{3}*7*\frac{1}{2}*5*5\\V_{1} = 29.17[/tex]
[tex]V_{2} = sh\\V_{2} = 4*\frac{1}{2}*5*5 \\V_{2} = 50[/tex]
- Total Volume of paperweight will be [tex]V_{1}+V_{2}[/tex]
∴ Total volume
[tex]=50+29.17\\=79.17[/tex]
Therefore the total volume of paperweight will be 79.17 cubic inch
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