contestada

Find the exact values of the six trigonometric functions of A given the point (-3, 7) on the terminal side of A in standard position.

Respuesta :

sqdancefan

Answer:

  • sin(A) = (7√58)/58
  • cos(A) = (-3√58)/58
  • tan(A) = -7/3
  • csc(A) = (√58)/7
  • sec(A) = (-√58)/3
  • cot(A) = -3/7

Step-by-step explanation:

The distance from the origin to the point is given by the distance formula:

  d = √((-3)² +7²) = √58

The three primary functions are ...

  sin(A) = y/d = (7√58)/58

  cos(A) = x/d = (-3√58)/58

  tan(A) = y/x = -7/3

__

The three secondary functions are the inverses of these:

  csc(A) = 1/sin(A) = (√58)/7

  sec(A) = 1/cos(A) = (-√58)/3

  cot(A) = 1/tan(A) = -3/7

Otras preguntas