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Given the information shown in process "B", calculate the molar enthalphy of fusion for ice

A) 40.1 kJ/mol
B) 4.50 kJ/mol
C) 18.0 kj/mol
D) 6.02 kJ/mol

Given the information shown in process B calculate the molar enthalphy of fusion for ice A 401 kJmol B 450 kJmol C 180 kjmol D 602 kJmol class=

Respuesta :

Answer:

D) 6.02 kJ/mol

Explanation:

Hello,

In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:

[tex]n=\frac{1.5kg}{18kg/kmol} *\frac{1000mol}{1kmol}=83.33mol[/tex]

Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:

[tex]\Delta H_{fusion}=\frac{500kJ}{83.33mol}\\ \\\Delta H_{fusion}=6.02kJ/mol[/tex]

Hence answer is D) 6.02 kJ/mol.

Best regards.