Answer:
3.60 ml
Explanation:
First of all we must put down the equation of the reaction. This will serve as a guide to our solution;
KOH(aq) + HBr(aq) -----> KBr(aq) + H2O(l)
The following were given in the question;
Concentration of acid CA= 2M
Volume of acid VA= 18ml
Concentration of base CB= 0.01 M
Volume of base VB= ????
Number of moles of acid NA= 1
Number of moles of base NB= 1
From;
CAVA/CBVB = NA/NB
CAVANB= CBVBNA
Therefore;
VB= CAVANB/CBNA
Substituting values;
VB= 2 × 18 ×1 / 0.01×1
VB= 3.60 ml
Therefore; 3.60 ml of base was used.
