Answer:
From the figure given we know that the lower base measures 7+7 = 14 representing the distance between the point B and C
For the upper base the distance between the point A and D is 5+3 = 8
The height can be founded from the distance between the point A and the lower base and we see that the hight is [tex] h = 5+4 =9[/tex]
Then the area can be founded with this formula:
[tex] A = \frac{AD+ BC}{2} *h[/tex]
And replacing we got:
[tex] A = \frac{8+14}{2} *9 = 99 units^2[/tex]
Step-by-step explanation:
We can olve the problem with this way much easier.
From the figure given we know that the lower base measures 7+7 = 14 representing the distance between the point B and C
For the upper base the distance between the point A and D is 5+3 = 8
The height can be founded from the distance between the point A and the lower base and we see that the hight is [tex] h = 5+4 =9[/tex]
Then the area can be founded with this formula:
[tex] A = \frac{AD+ BC}{2} *h[/tex]
And replacing we got:
[tex] A = \frac{8+14}{2} *9 = 99 units^2[/tex]
