Answer:
[tex]$\text{sin}(x)=\frac{12}{13} $[/tex]
[tex]$\text{cos}(x)=\frac{5}{13} $[/tex]
[tex]$\text{tan}(x)=\frac{12}{5} $[/tex]
Step-by-step explanation:
Consider:
[tex]$\text{sin}(x)=\frac{\text{Opposite}}{\text{Hypotenuse}} $[/tex]
[tex]$\text{cos}(x)=\frac{\text{Adjacent}}{\text{Hypotenuse}} $[/tex]
[tex]$\text{tan}(x)=\frac{\text{Opposite}}{\text{Adjacent}} $[/tex]
I will apply adjacent side to angle [tex]x[/tex] as 5. and opposite side to angle [tex]x[/tex] as 12.
So,
[tex]$\text{sin}(x)=\frac{12}{13} $[/tex]
[tex]$\text{cos}(x)=\frac{5}{13} $[/tex]
[tex]$\text{tan}(x)=\frac{12}{5} $[/tex]
