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An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled during that time?

Respuesta :

Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

[tex]d=10\times 8+\dfrac{1}{2}\times 3.5\times 8^2\\\\d=192\ m[/tex]

So, the distance travelled by the object is 192 meters.

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