The radius of a cylinder is 4 inches and the height is 5 inches. Which statements are correct? Check all that apply.

The area of the two bases is 16π in2.
The area of the two bases is 32π in2.
The lateral area is 40π in2.
The lateral area is 72π in2.
The total surface area is 72π in2.

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Answer:

2) The area of the two bases is 32π in2.

3) The lateral area is 40π in2.

5) The total surface area is 72π in2.

Step-by-step explanation:

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As per the given radius of the cylinder [tex]= 4[/tex] inches and height of the cylinder [tex]= 5[/tex] inches correct statement are

The area of the two bases is [tex]32\pi in^{2}[/tex] .

The lateral area is [tex]40\pi in^{2}[/tex].

The total surface area is [tex]72\pi in^{2}[/tex]

What is area?

" Area is defined as the total space occupied by two dimensional object enclosed in it."

Formula used

Area of the base of the cylinder [tex]= \pi r^{2}[/tex]

Lateral surface area of the cylinder [tex]= 2\pi rh[/tex]

Total surface area of the cylinder [tex]= 2\pi r^{2} + 2\pi rh[/tex]

According to the question,

Given ,

Radius of the cylinder [tex]= 4[/tex] inches

Height of the cylinder [tex]= 5[/tex] inches

Substitute the value in the formula of required area we get,

Area of the base of the cylinder [tex]= \pi \times (4^{2})[/tex]

                                                      [tex]= 16\pi in^{2}[/tex]

Area of the two base of the cylinder [tex]= (16\pi + 16\pi ) in^{2}[/tex]

                                                             [tex]= 32\pi in^{2}[/tex]

Lateral surface area of the cylinder [tex]= 2\pi \times 4\times 5[/tex]

                                                            [tex]= 40\pi in^{2}[/tex]

Total surface area of the cylinder [tex]= 32\pi + 40 \pi[/tex]

                                                         [tex]= 72\pi in^{2}[/tex]

Hence, as per the given radius of the cylinder [tex]= 4[/tex] inches and height of the cylinder [tex]= 5[/tex] inches correct statement are

The area of the two bases is [tex]32\pi in^{2}[/tex] .

The lateral area is [tex]40\pi in^{2}[/tex].

The total surface area is [tex]72\pi in^{2}[/tex]

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