Respuesta :

Answer:

A

Step-by-step explanation:

Given

y = [tex]\frac{x(x+2)}{x(x-3)}[/tex] ← cancel x on numerator/ denominator

 = [tex]\frac{x+2}{x-3}[/tex]

Cancelling the factor x, leaves a hole in the graph at x = 0

Answer:

A) x = 0

Step-by-step explanation:

edg