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Which system of equations can be used to find the roots of the equation 12 x cubed minus 5 x = 2 x squared + x + 6? StartLayout Enlarged left-brace 1st Row y = 12 x cubed minus 5 x 2nd row y = 2 x squared + x + 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed minus 5 x + 6 2nd row y = 2 x squared + x EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x 2nd row y = 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x + 6 2nd row y = 0 EndLayout

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Answer:

A

Step-by-step explanation:

12x³-5x=2x²+x+6

y=12x³-5x

y=2x²+x+6

MrRoyal

A system of equations is a collection of related equations

The system of equations that can be used to solve [tex]12x^3 - 5x = 2x ^2 + x + 6[/tex] [tex]y = 2x ^2 + x + 6[/tex] and [tex]y= 12x^3 - 5x[/tex]

The equation is given as:

[tex]12x^3 - 5x = 2x ^2 + x + 6[/tex]

Split the above equation into 2, and set both equations to 0

[tex]12x^3 - 5x = 0[/tex]

[tex]2x ^2 + x + 6 = 0[/tex]

Replace the "0" with y, in both equations

[tex]12x^3 - 5x = y[/tex]

[tex]2x ^2 + x + 6 = y[/tex]

Rewrite the equations as:

[tex]y = 2x ^2 + x + 6[/tex]

[tex]y= 12x^3 - 5x[/tex]

Hence, [tex]y = 2x ^2 + x + 6[/tex] and [tex]y= 12x^3 - 5x[/tex] can be used to solve [tex]12x^3 - 5x = 2x ^2 + x + 6[/tex]

Read more about system of equations at:

https://brainly.com/question/14323743

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