Answer:
140 L
Explanation:
Step 1: Write the balanced equation
2 H₂(g) + O₂(g) → 2 H₂O(g)
Step 2: Calculate the moles corresponding to 100 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
[tex]100g \times \frac{1mol}{32.00g} =3.13mol[/tex]
Step 3: Calculate the moles of water vapor formed
The molar ratio of oxygen to water vapor is 1:2.
[tex]3.13molO_2 \times \frac{2molH_2O}{1molO_2} =6.26molH_2O[/tex]
Step 4: Calculate the volume corresponding to 6.26 moles of water vapor
1 mole of any ideal gas under STP has a volume of 22.4 L.
[tex]6.26mol \times \frac{22.4L}{mol} =140 L[/tex]
