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Mark, Jhon and Stephanie, three archers, are aiming at a target. Each of them has only one shot. Mark has 1/5 chance of hitting the bullseye, Jhon has 1/4 chance and Stephanie has 1/3 chance.

a. what are the chances of the bullseye being hit

b. what are the chances that if only one of them hit the bullseye, Mark was the one who hit it.

Respuesta :

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For A:

You add the probabilities to get the answer to A: = .75, or 3/4

Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.

For B:

2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)

1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2

Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10

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