Respuesta :

TheLazyNobita

Answer:

The lines are parallel , so angle A and angle B form exterior alternate angles. Thus they are equal

[tex]\angle A = \angle B[/tex]

[tex]6x - 2 = 4x + 48[/tex]

[tex]2x = 50 [/tex]

[tex]x = 25[/tex]

Thus [tex]\angle A = 6(25) - 2 = 148[/tex]

devishri1977

Answer:

Step-by-step explanation:

Parallel lines. Alternate exterior angles are equal

∠A  = ∠B

6x - 2 = 4x + 48

Add 2 to both sides

6x - 2 + 2 = 4x + 48 + 2

6x = 4x + 50

Subtract 4x from both the sides

6x - 4x = 4x + 50 - 4x

2x = 50

Divide both sides by 2

2x/2 = 50/2

x = 25

∠A = 6x - 2 = 6*25 - 2 = 150 - 2 = 148

∠A = 148°

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