–3 = –2x2 + 2x

–3 = –2(x2 – x)

–3 + = –2(x2 – x + )

StartFraction negative 7 Over 2 EndFraction = –2(x – StartFraction 1 Over 2 EndFraction)2

StartFraction 7 Over 4 EndFraction = (x – StartFraction 1 Over 2 EndFraction)2

The two solutions are Plus or minus StartFraction StartRoot 7 EndRoot Over 2 EndFraction

Respuesta :

Answer:

Determine the next step for solving the quadratic equation by completing the square.

0 = –2x2 + 2x + 3

–3 = –2x2 + 2x

–3 = –2(x2 – x)

–3 + = –2(x2 – x + )

StartFraction negative 7 Over 2 EndFraction = –2(x – StartFraction 1 Over 2 EndFraction)2

StartFraction 7 Over 4 EndFraction = (x – StartFraction 1 Over 2 EndFraction)2

The two solutions are Plus or minus StartFraction StartRoot 7 EndRoot Over 2 EndFraction

-7/2 = -2(x - ½)²

Step-by-step explanation:

0 = –2x^2 + 2x + 3

Subtract 3 from each side

-3 = –2x^2 + 2x

Factor out the -2

-3 =- 2(x^2 -x)

Take the coefficient of x and divide by 2 and square it

-1 /2 = -1/2 ^2 = 1/4

Add it to each side  Remember the -2 on the outside so we need to multiply it by -2  

-2 *1/4 =  -1/2

-3 -1/2= -2(x^2 -x +1/4)

-7/2 = -2(x^2 -x +1/4)

-7/2 = -2(x-1/2)^2

7/2 = -2(x - ½)²

CT0723

Answer:

-1/2

1/4

1/2

Step-by-step explanation:

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