Answer:
Elastic potential energy, [tex]E=2.35\times 10^{-8}\ J[/tex]
Explanation:
Charge, [tex]q=9.4\times 10^{-10}\ C[/tex]
Potential, V = 50 V
It is required to find the electric potential energy in a capacitor stored in it. The formula of the electric potential energy in a capacitor is given by :
[tex]E=\dfrac{1}{2}qV\\\\E=\dfrac{1}{2}\times 9.4\times 10^{-10}\times 50\\\\E=2.35\times 10^{-8}\ J[/tex]
So, the electric potential energy stored in the capacitor is [tex]2.35\times 10^{-8}\ J[/tex]
