Answer:
4.65L
Explanation:
Equation of reaction,
Zn + 2HCl → H₂ + ZnCl₂
From the equation of reaction,
1 mole of Zn produce 1 mole of H₂
Number of mole = mass / molar mass
Molar mass of Zn = 65g/mol
Molar mass of H₂ = 2.0g/mol
Mass of Zn = 65g
Mass of H₂ = 2.0g
Therefore,
65g of Zn will produce 2g of H₂
13.5g of Zn will produce yg of H₂
Y = (13.5 × 2) / 65
Y = 0.415g of H₂
13.5g of Zn will produce 0.415g of H₂
From ideal gas equation,
PV = nRT
P = pressure of the gas
V = volume the gas occupies
n = number of moles of the gas
R = ideal gas constant = 0.082J/mol.K
T = temperature of the gas
At STP,
P = 1.0atm
V = ?
n = number of moles = mass / molar mass = 0.415 / 2 = 0.2075moles
R = 0.082J/mol.K
T = 273.15K
PV = nRT
V = nRT / P
V = (0.2075 × 0.082 × 273.15) / 1
V = 4.647L
Volume of the gas occupies is approximately 4.65L
