100 points to Answer Please
What is the y-intercept of the line perpendicular to the line y = three fourthsx + 3 that includes the point (3, 1)?

negative five fourths
3
negative thirteen fourths
5

Respuesta :

Answer:

5

Step-by-step explanation:

Let's convert those words into a line in slope intercept form. From what you said, the equation of a line perpendicular to the desired one is is [tex]y=\frac{3}{4}x+3[/tex]. The slope of this line is [tex]\frac{3}{4}[/tex], since the slope intercept form is y=mx+b, where m is the slope and b is the y intercept. The slope of a line perpendicular to this one is the negative reciprocal, or [tex]-\frac{4}{3}[/tex]. Since the line passes through the point (3,1), we can count backwards to find where the y intercept is (where x is 0). Since the slope is negative, for every unit you go backward on the x axis, you rise 4/3 on the y axis. Going backwards 3 units, then, will take you up 12/3, or 4 units. Adding this to the initial x value of the point of 1, you get a y value of 5. Hope this helps!

Answer:

5

Step-by-step explanation:

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