Respuesta :

Answer:

  [tex]f(x)=-\dfrac{14(x-3)(x-6)}{9(x+1)(x-4)}[/tex]

Step-by-step explanation:

The vertical asymptotes will be found where the denominator is zero. The x-intercepts will be found where the numerator is zero. The y-intercept can be made what you like using a suitable vertical scale factor.

Denominator factors: (x+1), (x-4) . . . . make the vertical asymptotes

Numerator factors: (x-6), (x-3) . . . . make the x-intercepts.

Now, our function is ...

  f(x) = a(x -6)(x -3)/((x +1)(x -4))

The y-intercept for this is ...

  f(0) = a(-6)(-3)/(1(-4)) = a(-18/4) = -9a/2

We want to choose "a" so this is 7:

  7 = -9a/2

  -14/9 = a . . . . multiply by -2/9

The rational function you want is ...

  [tex]\boxed{f(x)=-\dfrac{14(x-3)(x-6)}{9(x+1)(x-4)}}[/tex]

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