Respuesta :
Answer:
We need to remember that the limits for this correlation coefficient are [tex]-1 \leq r \leq 1[/tex]
So then for the firt question:
Since the |r| =0.94 and is near to 1 we can ensure that we have a strong relationship between the two variables of interest
And for the second question:
The slope for this case would be negative since if one variable increase the other decrease (that represent the negative value for r)
Step-by-step explanation:
For this case we are comparing the number of tardies. x, a student had when compared to their grade point average y.
We alo know that the correlation coefficient between the two variables using this formula:
[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]
And for this case [tex] r =-0.94[/tex]
We need to remember that the limits for this correlation coefficient are [tex]-1 \leq r \leq 1[/tex]
So then for the firt question:
Since the |r| =0.94 and is near to 1 we can ensure that we have a strong relationship between the two variables of interest
And for the second question:
The slope for this case would be negative since if one variable increase the other decrease (that represent the negative value for r)
