Caden rolls two fair number cubes numbered from 1 to 6. He first defines the sample space, as shown below:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Based on the sample space, what is the probability of getting a total of 6?
ps. I need the answer in a fraction, plsssss

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favorable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.

The probability formula defines the likelihood of the happening of an event. It is the ratio of favorable outcomes to the total favorable outcomes. The probability formula can be expressed as,

probability formula :

P(B)= n(B) / n(S)

where,

P(B) is the probability of an event 'B'.
n(B) is the number of favorable outcomes of an event 'B'.
n(S) is the total number of events occurring in a sample space.

Probability(Event) = Favorable Outcomes/Total Outcomes = x/n

As, the dice outcomes are given

Now, there are 5 outcomes who sum up to 6.

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

So, the probability of getting total 6 = 5/36

Learn more about probability here:

https://brainly.com/question/11234923

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