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If a 0.7 kg object hanging from a spring stretches it by 0.90 m, then by how much will the spring be stretched (in m) if a 1.4 kg object is suspended from it?
m

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Answer:

y/1.4 = 0.9/0.7

y= 0.9/0.7 x 1.4 = 1.8m

asuwafohjames

The extension of the spring when an object of mass 1.4 kg is placed on it is 1.8 m.

To calculate the amount at which the spring will stretch, we must first find the force constant of the spring

What is force constant?

Force constant is the ratio of the force to the extension of an elastic material.

The formula of force constant is

  • k = F/e............. Equation 1

From the question,

Given:

  • F = mg = 0.7×9.8 = 6.86 N
  • e = 0.9 m

Substitute these values into equation 1

  • k = 6.86/0.9
  • k = 7.62 N/m.

Finally, to calculate the extension if a 1.4 kg object is suspended from it, we use the formula below

  • e = F/k................. Equation 2

Given:

  • k = 7.62 N/m
  • F = 1.4×9.8 = 13.72 N

Substitute these values into equation 2

  • e = 13.72/7.62
  • e = 1.8 m

Hence, the extension of the spring when an object of mass 1.4 kg is placed on it is 1.8 m.

Learn more about force constant here: https://brainly.com/question/21257107

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