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Which equation, when solved, results in a different value of x than the other three?

Negative StartFraction 7 over 8 EndFraction x minus three-fourths = 20

Three-fourths + StartFraction 7 over 8 EndFraction x = negative 20

Negative 7 (StartFraction 1 over 8 EndFraction) x minus three-fourths = 20

Negative StartFraction 7 over 8 EndFraction (Negative StartFraction 8 over 7 EndFraction) x minus three-fourths = 20 (Negative StartFraction 8 over 7 EndFraction)


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Answer:

D

Explanation:

Given Option A: [TeX]-\frac{7}{8}x-\frac{3}{4}=20[/tex]

If we factor out the negative on the left hand side, we obtain:

[TeX]-(\frac{7}{8}x+\frac{3}{4})=20[/tex]

Dividing both sides by negative, we have:

[TeX]\frac{7}{8}x+\frac{3}{4}=-20[/tex]

Which is Option B.

Again from Option A

[TeX]-\frac{7}{8}x-\frac{3}{4}=20[/tex]

[TeX]-7(\frac{1}{8})x-\frac{3}{4}=20[/tex]

This is option C.

Therefore, A,B and C are equivalent and will give the same value for x.

Option D is the odd one out.

sontaydarrick

Answer:

Which rational number is the additive inverse of -0.75?

Negative three-fourths

StartFraction 7 over 5 EndFraction

Three-fourths

Negative four-thirds

Explanation:

Three-fourths

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